pairing up edges can be done almost entirely with the method shown below, the idea is a very familiar one, fix something, replace it with something else to move the fixed group out of the way, then undo the moves used fixing the first group to restore the centers.
|r' F R F' r|
matched pair cycle
now for the last 2 sets of edges, this can get a little tight because there is no third set of pieces to trade out, but these can be fixed easily with the following algorithm. if the matching pieces are diagonal from each other instead of across they can be swapped around into this position without doing any deep layer cuts, its just a matter of rearranging using such moves as L' F U'. this alg (like all) is easier to remember if you see what it's doing. first it knocks an edge out with its match, only reversed (Dd)'. then it removes that new pair and reinserts it upside down (F U F' L F' L' F), so that when you slice it back (Dd), the edges will match.
|d R U R' F R' F' R d'|
this is a more advanced method of solving edges, known as "chain solving". there are two main ideas on this method, the two at once and the six at once method, however the revenge can be set up as many different cycles. they both have advantages and disadvantages to them.
two pairs at once
the two at once method is shown below. the idea is that when we match up a set of edges, we replace them with the correct group that when we slice back, it fixes another group. in this case we are fixing the blue/yellow dedge. after we pair it up we replace that group with the correct edge (in the correct orientation also, otherwise it won't pair up) for fixing the green/white dedge. for an in-depth description of this method check out chris hardwick's page. for a complete video walkthrough of this method click here. most of the great revenge solvers use the E ring to pair stuff up, but the M ring is also usable for good times.
|d' F' L F L' d|
six pairs at once
this is the 6 at once method. it uses the same idea as the 2 at once, except it expands it further than just 2 pairs. this method accomplishes a lot at once, however some problems can arise in this method that won't happen in the 2 at once method.
sometimes the cycle falls short (ie: the piece you need to use is already in the build ring, in this case the OW edge). one of 2 things will happen, its either oriented correctly to finish the dedge, or it is not. if the orientation is correct, you can just match them, then shoot that piece out, replace it with a different group, then undo the matching move you made for the original dedge pair and continue the process with the new group.
if the piece needed is on the same inner slice as its match(ie: oriented incorrectly, and shown below with the OW edge), then i will shoot the dedge with the needed piece out, replace it with some other non matched pair, and reinsert it in the correct slot with correct orientation.
this pairing will start with the Fru edge, and work counter clockwise around the cube, then come back the clockwise way. order is RW,OW,BW,(insert random unfixed pair) BY,BR. just the first cycle of this method is show below. you will typically have to follow this with a '2 at once' cycle, a 'matched pair' cycle, or both. for a complete walkthrough check out this video.
there are a lot of possiblilties for chain solving. another popular choice is 3-2-3. all have their advantages and disadvantages, be sure to try a little everything to see what sticks for you.
|centers progress gauge|
|master edges||<30 seconds||you have no problems finding pieces or dealing with weird cases. there is little or no delay between each sequence.|
|intermediate edges||<60 seconds||You can quickly find the pieces you need, but sometimes there is a delay or the insertion ends up going wrong. as always slowing down is the key to make sure each turn is optimized for what you're trying to do.|
|beginner edges||60+ seconds||you can assemble the edges, but have difficult finding the pieces you need. the setup moves might be confusing or hard to see. be assured slow and steady practice will move your times down quickly.|
on to the final solve
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